MATH SOLVE

10 months ago

Q:
# The sum of 3 consecutive integers is 72 find the integers

Accepted Solution

A:

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Define x :

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Let the smallest number be x.

The other two numbers will be x + 1 and x + 2.

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Construct Equation :

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Sum of these numbers is 72

β x + x + 1 + x + 2 = 72

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Solve for x :

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x + x + 1 + x + 2 = 72

3x + 3 = 72

3x = 69

x = 23

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Find the numbers :

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1st number = x = 23

2nd number = x + 1 = 23 + 1 = 24

3rd number = x + 2 = 23 + 2 = 25

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Answer : The numbers are 23, 24 and 25.

----------------------------------------------------------------------------------

Define x :

-----------------------------------------

Let the smallest number be x.

The other two numbers will be x + 1 and x + 2.

-----------------------------------------

Construct Equation :

-----------------------------------------

Sum of these numbers is 72

β x + x + 1 + x + 2 = 72

-----------------------------------------

Solve for x :

-----------------------------------------

x + x + 1 + x + 2 = 72

3x + 3 = 72

3x = 69

x = 23

-----------------------------------------

Find the numbers :

-----------------------------------------

1st number = x = 23

2nd number = x + 1 = 23 + 1 = 24

3rd number = x + 2 = 23 + 2 = 25

----------------------------------------------------------------------------------

Answer : The numbers are 23, 24 and 25.

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