MATH SOLVE

10 months ago

Q:
# 7. Use the discriminant to determine how many real number solutions exist for the quadratic equation –4j2 + 3j – 28 = 0.

Accepted Solution

A:

[tex]\bf \begin{array}{llccll}
y=&{{ -4}}j^2&{{ +3}}j&{{ -28}}\\
&~\uparrow &\uparrow &\uparrow \\
&~a&b&c
\end{array}
\\\\\\
discriminant\implies b^2-4ac=
\begin{cases}
0&\textit{one solution}\\
positive&\textit{two solutions}\\
negative&\textit{no solution}
\end{cases}[/tex]

so.. check what value the discriminant is then.

so.. check what value the discriminant is then.