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Solve 2x2 + 20x = β38. (1 point)
9 months ago
Q:
Solve 2x2 + 20x = β38. (1 point)
Accepted Solution
A:
[tex]Pull \ out \ like \ factors : \\ \\ 42 + 20x = 2 * (10x + 21) \ \\ \\ Solve : \ 2 = \ 0 \\ \\ Subtract 21 from both sides of the equation : \\ 10x = -21 \\ \\ Divide both sides of the equation by 10: \\ \\ x = -21/10 = \boxed{-2.100 } [/tex]