MATH SOLVE

9 months ago

Q:
# (-2x5 - 4x3 - x2 -80) % (x-2)

Accepted Solution

A:
$=-2x^{4}+\frac{-4x^{4}-4x^{3}-x^{2}-80}{x-2}$

$=-2x^{4}-4x^{3}+\frac{-12x^{3}-x^{2}-80}{x-2}$

$=-2x^{4}-4x^{3}-12x^{2}+\frac{-25x^{2}-80}{x-2}$

$=-2x^{4}-4x^{3}-12x^{2}-25x+\frac{-50x-80}{x-2}$

$=-2x^{4}-4x^{3}-12x^{2}-25x-50+\frac{-180}{x-2}$

$=-2x^{4}-4x^{3}-12x^{2}-25x-50-\frac{180}{x-2}$