A body is thrown vertically upward with a velocity of 300 m/s. a) What is its velocity after 10 s? b) How high will it be after 10 seconds?

To solve this problem, we need to use the equations of motion for a body thrown vertically upward with a constant acceleration due to gravity. The acceleration due to gravity is usually denoted by g and has a value of approximately 9.8 m/s^2 on Earth. The equations of motion are: v = u - gt $$s = ut - \frac{1}{2}gt^2$$ where v is the final velocity, u is the initial velocity, t is the time, and s is the displacement. In this problem, we have: u = 300 m/s t = 10 s g = 9.8 m/s^2 We can plug these values into the equations of motion to find v and s. (a) To find the final velocity after 10 s, we use the equation: v = u - gt $$v = 300 - 9.8 \times 10$$ v = 202 m/s Therefore, the final velocity after 10 s is 202 m/s. (b) To find the displacement after 10 s, we use the equation: $$s = ut - \frac{1}{2}gt^2$$ $$s = 300 \times 10 - \frac{1}{2} \times 9.8 \times 10^2$$ s = 3000 - 490 s = 2510 m Therefore, the displacement after 10 s is 2510 m.