MATH SOLVE

4 months ago

Q:
# A body is thrown vertically upward with a velocity of 300 m/s. a) What is its velocity after 10 s? b) How high will it be after 10 seconds?

Accepted Solution

A:

To solve this problem, we need to use the equations of motion for a body thrown vertically upward with a constant acceleration due to gravity. The acceleration due to gravity is usually denoted by g and has a value of approximately 9.8 m/s^2 on Earth. The equations of motion are:
v = u - gt
$$s = ut - \frac{1}{2}gt^2$$
where v is the final velocity, u is the initial velocity, t is the time, and s is the displacement.
In this problem, we have:
u = 300 m/s
t = 10 s
g = 9.8 m/s^2
We can plug these values into the equations of motion to find v and s.
(a) To find the final velocity after 10 s, we use the equation:
v = u - gt
$$v = 300 - 9.8 \times 10$$
v = 202 m/s
Therefore, the final velocity after 10 s is 202 m/s.
(b) To find the displacement after 10 s, we use the equation:
$$s = ut - \frac{1}{2}gt^2$$
$$s = 300 \times 10 - \frac{1}{2} \times 9.8 \times 10^2$$
s = 3000 - 490
s = 2510 m
Therefore, the displacement after 10 s is 2510 m.