MATH SOLVE

6 months ago

Q:
# PLEASE HELP AND SHOW ALL WORK7.04Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false.(4 points each.)1. 4 ⋅ 6 + 5 ⋅ 7 + 6 ⋅ 8 + ... + 4n( 4n + 2) = quantity four times quantity four n plus one times quantity eight n plus seven divided all divided by six2. 12 + 42 + 72 + ... + (3n - 2)2 = quantity n times quantity six n squared minus three n minus one all divided by twoFor the given statement Pn, write the statements P1, Pk, and Pk+1.(2 points)2 + 4 + 6 + . . . + 2n = n(n+1)

Accepted Solution

A:

1]

4*6+5*7+6*8+.....+4n(4n+2)=4(4n+1)(8n+7)/6

If we choose n=1, then 4*6=24 but 4(4*1+1)(8*1+7)/6=50. This implies that the general trm for the pattern shown is wrong. It should have been (n+3)(n+5) and not 4n(4n+2).

2] 12+42+72+.......+(3n-2)2=n(6n²-3n-1)/2

Let's set n=1, this means that 12=12.

But n(6n²-3n-1)/2

=1(6*1²-3*1-1)/2

=(6-3-1)/2

=2/2

=1

This shows that the general term is incorrect. It should have been (30n-18) which when simplified we get 6(5n-3). Even if we get to correct the left hand side the sequence will still not be equal to what's on the right given n=1.

3] 2+4+6+....+2n=n(n+1)

P(1):2=1(1+1)

P(m):2+4+6+..+2m=m(m+1)

P(m+1):2(k+1)=(k+1)(k+2)

4*6+5*7+6*8+.....+4n(4n+2)=4(4n+1)(8n+7)/6

If we choose n=1, then 4*6=24 but 4(4*1+1)(8*1+7)/6=50. This implies that the general trm for the pattern shown is wrong. It should have been (n+3)(n+5) and not 4n(4n+2).

2] 12+42+72+.......+(3n-2)2=n(6n²-3n-1)/2

Let's set n=1, this means that 12=12.

But n(6n²-3n-1)/2

=1(6*1²-3*1-1)/2

=(6-3-1)/2

=2/2

=1

This shows that the general term is incorrect. It should have been (30n-18) which when simplified we get 6(5n-3). Even if we get to correct the left hand side the sequence will still not be equal to what's on the right given n=1.

3] 2+4+6+....+2n=n(n+1)

P(1):2=1(1+1)

P(m):2+4+6+..+2m=m(m+1)

P(m+1):2(k+1)=(k+1)(k+2)