mrs.beluga is driving on a snow covered road with a drag factor of 0.2. she brakes suddenly for a deer. The tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet. What is the minimum speed she could have been going?

First, we are going to find the radius of the yaw mark. To do that we are going to use the formula: [tex]r= \frac{c^2}{8m} + \frac{m}{2} [/tex]
where 
[tex]c[/tex] is the length of the chord 
[tex]m[/tex] is the middle ordinate 
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so [tex]c=52[/tex] and [tex]m=6[/tex]. Lets replace those values in our formula:
[tex]r= \frac{52^2}{8(6)} + \frac{6}{2} [/tex]
[tex]r= \frac{2704}{48} +3[/tex]
[tex]r= \frac{169}{3} +3[/tex]
[tex]r= \frac{178}{3} [/tex]

Next, to find the minimum speed, we are going to use the formula: [tex]s= \sqrt{15fr} [/tex]
where
[tex]f[/tex] is drag factor
[tex]r[/tex] is the radius 
We know form our problem that the drag factor is 0.2, so [tex]f=0.2[/tex]. We also know from our previous calculation that the radius is [tex] \frac{178}{3} [/tex], so [tex]r= \frac{178}{3}[/tex]. Lets replace those values in our formula:
[tex]s= \sqrt{(15)(0.2)( \frac{178}{3}) } [/tex]
[tex]s= \sqrt{178} [/tex]
[tex]s=13.34[/tex] mph

We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was 13.34 miles per hour.