Find the midpoint of the line segment joining the points (10,7) and (negative 2,negative 7).
Accepted Solution
A:
The midpoint of the line segment joining the points (10,7) and (negative 2,negative 7) is (4, 0)Solution:Given that line segment joining the points (10,7) and (negative 2, negative 7)Thus the two points are (10, 7) and (-2, -7)The midpoint of two points [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] is given as:[tex]M(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)[/tex][tex]\text {Here } x_{1}=10 \text { and } y_{1}=7 \text { and } x_{2}=-2 \text { and } y_{2}=-7[/tex]Substituting the values in formula, we get[tex]\begin{array}{l}{M(x, y)=\left(\frac{10+(-2)}{2}, \frac{7+(-7)}{2}\right)} \\\\ {M(x, y)=\left(\frac{10-2}{2}, \frac{7-7}{2}\right)} \\\\ {M(x, y)=(4,0)}\end{array}[/tex]Thus the midpoint of line segment is (4, 0)