A salesman used three types of order forms: A, B, C. He used 40 of Form A. Of Form B he used four times as many as Form A plus 1/2 as many as Form C. He used as many of Form C as Form A plus 1/2 as many as Form B. Altogether, how many forms did he use? Clear 0A. 440 B. 200 C. 250 D. 320 E. 500

Answer:a. 440Step-by-step explanation:The information provided allows us to set up the following system of linear equations:[tex]A = 40\\B=4A+0.5C\\C=A+0.5B[/tex]We already have the value for A, solving the system gives us the values for B and C:[tex]A = 40\\B=(4*40)+0.5C\\C=40+0.5B\\\\B -B-80 = (4*40)+0.5C-2C\\C=\frac{160+80}{1.5}\\C=160\\B= (4*40) +(0.5*160)\\B=240[/tex]The total number of forms used is:[tex]A+B+C = 40+240+160 = 440[/tex]He used 440 forms.