17] The distance, x, between the farmhouse and water tower will be given by: Tan θ=opposite/adjacent adjacent=opposite/tan θ thus: x=500/tan 12-500/tan 16 x=500/0.2126-500/0.2868 x=608.61 yd ~609 yd
Answer: D] about 609 yd
18] The angle of depression will be: tan θ=opposite/adjacent thus tan θ=0.5/13 tan θ=0.0385 θ=arctan 0.0385 θ=2.2°
19] This will be evaluated like #17 above. Tan θ=opposite/adjacent adjacent=opposite/tan θ thus x=95/tan 31-95/tan42 x=95/0.6009-95/0.9004 x=52.598 ~53
answer: A] about 53
20] The horizontal length will be calculated as follows: sin θ=opposite/hypotenuse opposite=73 m hypotenuse=177 m thus sinθ=73/177 sinθ=0.4124 θ=arcsin 0.4124 θ=24.357~24.4°