Your family goes out to Chili's for dinner. Chili's charges $9 for an adult dinner and $5 for achild's plate. Ten members of your family went to dinner and your bill was $66. How manyadults and children ate at Chili's?
Accepted Solution
A:
Answer:The number of adult's for the dinner is 4 and The number of child's for the dinner is 6 .Step-by-step explanation:Given as :The total number of members goes for dinner = 10The total bill for the dinner = $ 66Let The number of children goes for dinner = CAnd the number of adults goes for the dinner = AThe charges for the adults dinner = $ 9 per plateThe charges for the child dinner = $ 5 per plateSo, According to question A + C = 10 ......19 A + 5 C = 66 ....2Solving eq 1 and 2So, 9 × ( A + C ) = 9 × 10Or, 9 A + 9 C = 90 9 A + 5 C = 66or, ( 9 A + 9 C ) - ( 9 A + 5 C ) = 90 - 66Or, ( 9 A - 9 A ) + ( 9 C - 5 C ) = 24or , 0 + 4 C = 24 ∴ C = [tex]\frac{24}{4}[/tex]I.e C = 6 Put The value of C in eq 2so, 9 A + 5 C = 66 or, 9 A + 5 × 6 = 66 or, 9 A + 30 = 66 Or, 9 A = 66 - 30Or, 9 A = 36∴ A = [tex]\frac{36}{9}[/tex]i.e A = 4Hence The number of adult's for the dinner is 4 and The number of child's for the dinner is 6 . answer