MATH SOLVE

7 months ago

Q:
# Write the equation of the circle with center (−3, −2) and (4, 5) a point on the circle.

Accepted Solution

A:

1. distance = √((x₂-x₁)²+(y₂-y₁)²)= radius of the circle.

distance = √((4-(-3))²+(5-(-2))7²) = √98

2. (x-k)²+(y-h)²=r² center (-3,-2) which is (k,h)

(x-(-3))²+(y-(-2))²= (√98)²

(x+3)+(y+2)² = 98 is the equation

distance = √((4-(-3))²+(5-(-2))7²) = √98

2. (x-k)²+(y-h)²=r² center (-3,-2) which is (k,h)

(x-(-3))²+(y-(-2))²= (√98)²

(x+3)+(y+2)² = 98 is the equation