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Write the equation of the circle with center (β3, β2) and (4, 5) a point on the circle.
5 months ago
Q:
Write the equation of the circle with center (β3, β2) and (4, 5) a point on the circle.
Accepted Solution
A:
1. distance =Β β((xβ-xβ)Β²+(yβ-yβ)Β²)= radius of the circle.
distance =Β β((4-(-3))Β²+(5-(-2))7Β²) =Β β98
2. (x-k)Β²+(y-h)Β²=rΒ² center (-3,-2) which is (k,h)
(x-(-3))Β²+(y-(-2))Β²= (β98)Β²
(x+3)+(y+2)Β² = 98 is the equation