Q:

Write the equation of the circle with center (βˆ’3, βˆ’2) and (4, 5) a point on the circle.

Accepted Solution

A:
1. distance = √((xβ‚‚-x₁)Β²+(yβ‚‚-y₁)Β²)= radius of the circle.

distance = √((4-(-3))²+(5-(-2))7²) = √98

2. (x-k)Β²+(y-h)Β²=rΒ² center (-3,-2) which is (k,h)

(x-(-3))²+(y-(-2))²= (√98)²

(x+3)+(y+2)Β² = 98 is the equation