MATH SOLVE

10 months ago

Q:
# Write the equation of the circle with center (β3, β2) and (4, 5) a point on the circle.

Accepted Solution

A:

1. distance =Β β((xβ-xβ)Β²+(yβ-yβ)Β²)= radius of the circle.

distance =Β β((4-(-3))Β²+(5-(-2))7Β²) =Β β98

2. (x-k)Β²+(y-h)Β²=rΒ² center (-3,-2) which is (k,h)

(x-(-3))Β²+(y-(-2))Β²= (β98)Β²

(x+3)+(y+2)Β² = 98 is the equation

distance =Β β((4-(-3))Β²+(5-(-2))7Β²) =Β β98

2. (x-k)Β²+(y-h)Β²=rΒ² center (-3,-2) which is (k,h)

(x-(-3))Β²+(y-(-2))Β²= (β98)Β²

(x+3)+(y+2)Β² = 98 is the equation