What is the value of the discriminant, b2 βˆ’ 4ac, for the quadratic equation 0 = x2 βˆ’ 4x + 5, and what does it mean about the number of real solutions the equation has?

Accepted Solution

Answer:Discriminant D = -4 , no real solutionStep-by-step explanation:Here our equation is [tex]x^{2}-4x+5=0[/tex]Discriminant (D)= [tex]b^2-4ac[/tex]where a = coefficient of term containing [tex]x^{2}[/tex] b= coefficient of the term containing [tex]x[/tex]c is the constant termhence a=1 , b =-4 and c=5Hence [tex]D=b^2-4ac\\D=(-4)^2-4*1*5\\D=16-20\\D=-4\\[/tex]Hence D is less than 0 , therefore we do not have any real solution to this quadratic equation.