What is the solution to the system of equations? 6x β 9y = 162x β 3y = 7
Accepted Solution
A:
The first step for solving this problem is to multiply both sides of the bottom equation by -3. [tex] \left \{ {{6x-9y=16} \atop {-6x + 9y = -21}} \right. [/tex] Add the two equations together. 6x - 9y - 6x + 9y = 16 - 21 Eliminate the opposites. -9y + 9y = 16 - 21 Remember that the sum of two opposites equals 0,, so the equation becomes the following: 0 = 16 - 21 Calculate the difference on the right side of the equation. 0 = -5 This means that the statementΒ [tex] \left \{ {{6x-9y=16} \atop {2x-3y=7}} \right. [/tex] is false for any value of x and y. That means that the answer to your question is (x,y)Β βΒ β ,, or no solution. Let me know if you have any further questions. :)