MATH SOLVE

5 months ago

Q:
# What is the perimeter of the rectangle shown on the coordinate plane, to the nearest tenth of a unit?A. 12.7 unitsB. 16.9 unitsC. 24.0 unitsD. 33.9 units

Accepted Solution

A:

What we know:

shape is rectangle which means the 2 long sides have equal distance and the 2 short sides have equal distance

we just need to find the distance of one long side and one short side for the perimeter which is the outline of the rectangle. Imagine the perimeter is the fence around the rectangle that you would probably have to paint every 3 years and the area would be where the grass would grow in the rectangle which you would probably have to cut every weekend.

perimeter=2l+2w

What we need to find: PERIMETER

Using pythagorean method a² +b²=h² to find length:

From point (-6,1) to point (3,8) is a rise of 9 and a run of 9 right to get from one point to another, those are my a and b in the pythagorean formula.

a² +b²=h²

(9)²+(9)²=h² substitution

81+81=h² simplified

162=h²

√162=√h2 used radical properties

√162=h length =√162

Using pythagorean method a² +b²=h² to find width:

From points (-6,-1) to point (-3,-4) is a down 3 units and left 3 units to reach from one point to another, these are my a and b for the pythagorean formula.

a² +b²=h²

(3)²+(3)²=h²

9+9=h²

18=h²

√18=√h²

√18=h this is the width=√18

Now we find perimeter:

p=2l+2w

p=2(√162)+2(√18)

p≈33.9

D. 33.9 units

shape is rectangle which means the 2 long sides have equal distance and the 2 short sides have equal distance

we just need to find the distance of one long side and one short side for the perimeter which is the outline of the rectangle. Imagine the perimeter is the fence around the rectangle that you would probably have to paint every 3 years and the area would be where the grass would grow in the rectangle which you would probably have to cut every weekend.

perimeter=2l+2w

What we need to find: PERIMETER

Using pythagorean method a² +b²=h² to find length:

From point (-6,1) to point (3,8) is a rise of 9 and a run of 9 right to get from one point to another, those are my a and b in the pythagorean formula.

a² +b²=h²

(9)²+(9)²=h² substitution

81+81=h² simplified

162=h²

√162=√h2 used radical properties

√162=h length =√162

Using pythagorean method a² +b²=h² to find width:

From points (-6,-1) to point (-3,-4) is a down 3 units and left 3 units to reach from one point to another, these are my a and b for the pythagorean formula.

a² +b²=h²

(3)²+(3)²=h²

9+9=h²

18=h²

√18=√h²

√18=h this is the width=√18

Now we find perimeter:

p=2l+2w

p=2(√162)+2(√18)

p≈33.9

D. 33.9 units