MATH SOLVE

10 months ago

Q:
# Ari's teacher says he may have his report grade based on either the mean or the median of his last six test scores. 88%, 73%, 97%, 76%, 90%, 80% which measure of center would best represent ari's grade? the mean the median both the mean and the median neither the mean nor the median

Accepted Solution

A:

Answer:Both the mean and the median

Step-by-step explanation:Whichever measure, mean or median, is higher, Ari will benefit from that.

Median:Median is the "middle value" of the list when arranged from least to greatest.Since there is 6 numbers, the middle number is between the 3rd and 4th number. Hence, we take the average of the 3rd and 4th number.Arranged from least to greatest: 73, 76, 80, 88, 90, 97Average of 3rd and 4th is the Median = [tex]\frac{80+88}{2}=\frac{168}{2}=84[/tex]

Mean:Mean is the sum of all the number divided by the number of numbers (6).So we have:Mean = [tex]\frac{88+73+97+76+90+80}{6}=\frac{504}{6}=84[/tex]Mean is 84

Since Mean and Median are both same (84%), both will be best measure of center for Ari.

Step-by-step explanation:Whichever measure, mean or median, is higher, Ari will benefit from that.

Median:Median is the "middle value" of the list when arranged from least to greatest.Since there is 6 numbers, the middle number is between the 3rd and 4th number. Hence, we take the average of the 3rd and 4th number.Arranged from least to greatest: 73, 76, 80, 88, 90, 97Average of 3rd and 4th is the Median = [tex]\frac{80+88}{2}=\frac{168}{2}=84[/tex]

Mean:Mean is the sum of all the number divided by the number of numbers (6).So we have:Mean = [tex]\frac{88+73+97+76+90+80}{6}=\frac{504}{6}=84[/tex]Mean is 84

Since Mean and Median are both same (84%), both will be best measure of center for Ari.