MATH SOLVE

9 months ago

Q:
# What is the general form of the equation for the given circle?A.x2 + y2 − 8x − 8y + 23 = 0B.x2 + y2 − 8x − 8y + 32 = 0C.x2 + y2 − 4x − 4y + 23 = 0D.x2 + y2 + 4x + 4y + 9 = 0

Accepted Solution

A:

Hello,

Answer A

B: x²+y²-8x-8y+32=0==>(x-4)²+(y-4)²=0 is a point, not a circle.

C:x²+y²-4x-y+23=0==>(x+2)²+(y-2)²=-15 is not a circle

D: x²+y²+4x+4y+9=0==>(x+2)²+(y+2)²=-1 is not a circle.

But;x²+y²-8x-8y+23=0==>(x-4)²+(y-4)=9 is a circle.

Answer A

B: x²+y²-8x-8y+32=0==>(x-4)²+(y-4)²=0 is a point, not a circle.

C:x²+y²-4x-y+23=0==>(x+2)²+(y-2)²=-15 is not a circle

D: x²+y²+4x+4y+9=0==>(x+2)²+(y+2)²=-1 is not a circle.

But;x²+y²-8x-8y+23=0==>(x-4)²+(y-4)=9 is a circle.