What is the equation of the line that is parallel to the line y = 1/3x + 4 and passes through the point (6, 5)? y = -1/3x + 3 y= -1/3x + 7 y= 3x - 13 y= 3x + 5
Accepted Solution
A:
-------------------------------------------------- Find Slope -------------------------------------------------- y = -1/3 x + 4 Slope = -1/3 Slope of the parallel line = -1/3
-------------------------------------------------- Insert slope into y = mx + c -------------------------------------------------- y = -1/3 x + c
-------------------------------------------------- Find y-intercept -------------------------------------------------- y = -1/3 x + c at point (6, 5) 5 = -1/3 (6) + c 5 = - 2 + c c = 5 + 2 c = 7
-------------------------------------------------- Insert y-intercept into y = -1/3x + c -------------------------------------------------- y = -1/3 x + 7
-------------------------------------------------- Answer: y = -1/3 x + 7 (Answer B) --------------------------------------------------