MATH SOLVE

7 months ago

Q:
# PLEASE HELP EASY ALGEBRA What is the sum of the geometric sequence 1, 3, 9, β¦ if there are 10 terms? A: 29,524 B: 55,987 C: 87,381 D: 88,573

Accepted Solution

A:

Each number in the 10-digit sequence is multiplied by 3

1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683

1*3= 3

3*3=9

9*3=27

27*3=81

81*3=243

243*3=729

729*3=2187

2187*3=6561

6561*3=19683

Total of numbers= 29524

ANSWER: A) 29,524

Hope this helps! :)

1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683

1*3= 3

3*3=9

9*3=27

27*3=81

81*3=243

243*3=729

729*3=2187

2187*3=6561

6561*3=19683

Total of numbers= 29524

ANSWER: A) 29,524

Hope this helps! :)