*hypotenuse is always the largest side, and the one opposite the 90° angle in right triangles
therefore we'll use SOH, because the opposite of x (O) and the hypotenuse (H) are given:
Sine (x) = Opposite/Hypotenuse Sine (x) = 32/58 = 16/29 = 0.552 Sine (x) = 0.552 now we use something called arc-sine, or [tex] {(sin)}^{ - 1} [/tex] it's basically a fancy function of most advanced calculators, so we'll plug it in as: [tex]x = {(sin)}^{ - 1} (0.552)[/tex] x = 33.49° --> answer B) is correct