MATH SOLVE

7 months ago

Q:
# The table shows the time a patient spends at the dentist and the amount of the bill.What is the correlation coefficient for the data in the table?–0.93–0.270.270.93

Accepted Solution

A:

Answer- Correlation coefficient for the data in the table was found to be 0.93.Solution-Taking the independent variable or input variable as, the time a patient spends at the dentist and the dependent variable or output variable as the amount of the bill.We know that,[tex]r=\frac{n(\sum xy)-\sum x \sum y}{\sqrt{[n\sum x^{2} -({\sum x})^{2}]\times [n\sum y^{2} -({\sum y})^{2}]}}[/tex]

Calculating the values from the table, then putting it in the formula[tex]r=\frac{4 \times 3130.9 \ - \ 6.45 \times 1473}{\sqrt{[4\times 12.3725 \ - \ 6.45^{2}][4 \times 877475 \ - \ 1473^2]}}[/tex][tex]\Rightarrow r=0.929720561 \approx 0.93[/tex]∴ Correlation coefficient for the data is 0.93.

Calculating the values from the table, then putting it in the formula[tex]r=\frac{4 \times 3130.9 \ - \ 6.45 \times 1473}{\sqrt{[4\times 12.3725 \ - \ 6.45^{2}][4 \times 877475 \ - \ 1473^2]}}[/tex][tex]\Rightarrow r=0.929720561 \approx 0.93[/tex]∴ Correlation coefficient for the data is 0.93.