Q:

Springs: A spring has a natural length of 0.1 m. If a 50-N force is required to keep it stretched to a length of 0.3 m, how much work is required to stretch it from 0.1 m to 0.2 m?

Accepted Solution

A:
Force = k × Distance 50 N = k × 0.3 k = 50 N / 0.3 k = 166.67 N/m Force required to stretch the spring to a length of 0.2 m. Force = k × Distance Force = 166.67 N/m × 0.2 m Force = 33.33 N Work = Force × Distance Work = 33.33 N × (0.2 m - 0.1 m) Work = 33.33 N × 0.1 m Work = 3.333 N·m or 3.333 Joules Work required to stretch the spring from 0.1 m to 0.2 m is 3.333 Joules