MATH SOLVE

10 months ago

Q:
# Springs: A spring has a natural length of 0.1 m. If a 50-N force is required to keep it stretched
to a length of 0.3 m, how much work is required to stretch it from 0.1 m to 0.2 m?

Accepted Solution

A:

Force = k × Distance
50 N = k × 0.3
k = 50 N / 0.3
k = 166.67 N/m
Force required to stretch the spring to a length of 0.2 m.
Force = k × Distance
Force = 166.67 N/m × 0.2 m
Force = 33.33 N
Work = Force × Distance
Work = 33.33 N × (0.2 m - 0.1 m)
Work = 33.33 N × 0.1 m
Work = 3.333 N·m or 3.333 Joules
Work required to stretch the spring from 0.1 m to 0.2 m is 3.333 Joules