mass 2 kg
horizontal plane
friction 0.5
constant velocity 3 m/s
for 5 seconds
What is the work?
Accepted Solution
A:
Work=Frictional Force × Distance × cos(θ)
Frictional Force=Frictional Coefficient × Normal Force
Normal Force=m⋅g=2(9.8)=19.6
Frictional Force=0.5×19.6=9.8
Work=Force×Distance×cos(θ)
Since the force and the direction of motion are in opposite directions,
cosθ=-1
Work=9.8N×3m×(−1)=−29.4Joules