Q:

Justin bought a calculafor and a binder that were both 15% off the original price. The original price of the binder was $6.20. Justin spent a total of $107.27. What was the original price of the calculator?

Accepted Solution

A:
Letx-----> the original price of the calculatory-----> the original price of the binderwe know that[tex]15\%= \frac{15}{100}=0.15[/tex][tex](x+y)(1-0.15)=107.27[/tex][tex](x+y)(0.85)=107.27[/tex] -----> equation A[tex]y=6.20[/tex] -----> equation Bsubstitute the value of y in the equation A and solve for x[tex](x+6.20)(0.85)=107.27[/tex] [tex](x+6.20)=(107.27/0.85)[/tex] [tex]x=(107.27/0.85)-6.20[/tex] [tex]x=126.20-6.20[/tex] [tex]x=\$120[/tex] thereforethe answer isthe original price of the calculator is [tex]\$120[/tex]