In a 45-45-90 triangle, what is the length of the hypotenuse when the length of one of the legs is 5 in.?5√2 in.5√5 in.√5 in.2√5 in.

The proportions in a 45-45-90 triangle are
1 : 1 : square root 2.

Finding the length of the hypotenuse can be done with the following formula:
length of a leg × square root of 2

Therefore in a 45-45-90 triangle with legs with a length of 5 inches, the hypotenuse is
[tex]5 \times \sqrt{2} = 5 \sqrt{2} \: in.[/tex]