MATH SOLVE

6 months ago

Q:
# I need help !! This packet is due tomorrow and I have no idea what I’m doing .

Accepted Solution

A:

The proof would be as follows:

Given: angle M congruent to angle X; angle N congruent to angle Y; YO congruent to NZ.

1. YZ=YO+OZ; reason: segment addition postulate (YZ is made up of YO and OZ).

2. ON=NZ+OZ; reason: segment addition postulate (ON is made up of NZ and OZ).

3. YO=NZ; reason: given.

4. ON=YO+OZ; reason: substitution (since NZ is congruent to YO, we substitute YO for NZ).

5. ON=YZ; reason: substitution (since YZ=YO+OZ, we substitute YZ for YO+OZ).

6. MNO is congruent to XYZ; reason: AAS (we have 2 sides and a non-included angle in each triangle congruent, which is the angle-angle-side theorem).

Given: angle M congruent to angle X; angle N congruent to angle Y; YO congruent to NZ.

1. YZ=YO+OZ; reason: segment addition postulate (YZ is made up of YO and OZ).

2. ON=NZ+OZ; reason: segment addition postulate (ON is made up of NZ and OZ).

3. YO=NZ; reason: given.

4. ON=YO+OZ; reason: substitution (since NZ is congruent to YO, we substitute YO for NZ).

5. ON=YZ; reason: substitution (since YZ=YO+OZ, we substitute YZ for YO+OZ).

6. MNO is congruent to XYZ; reason: AAS (we have 2 sides and a non-included angle in each triangle congruent, which is the angle-angle-side theorem).