MATH SOLVE

9 months ago

Q:
# WILL GIVE A BRAINLEST!!!!!!Solve and check : c-4/c-2=c-2/c+2 - 1/2-cThe solution is c =How many extraneous solutions are there?

Accepted Solution

A:

we have that

(c-4)/(c-2)=(c-2)/(c+2) - 1/(2-c)

- 1/(2-c)=-1/-(c-2)=1/(c-2)

(c-4)/(c-2)=(c-2)/(c+2)+ 1/(c-2)------- > (c-4)/(c-2)-1/(c-2)=(c-2)/(c+2)

(c-4-1)/(c-2)=(c-2)/(c+2)---------------- > (c-5)/(c-2)=(c-2)/(c+2)

(c-5)/(c-2)=(c-2)/(c+2)------------- > remember (before simplifying) for the solution that c can not be 2 or -2

(c-5)*(c+2)=(c-2)*(c-2)------------------ > c²+2c-5c-10=c²-4c+4

-3c-10=-4c+4----------------------------- > -3c+4c=4+10----------- > c=14

the solution is c=14

the domain of the function is (-∞,-2) U (-2,2) U (2,∞) or

all real numbers except c=-2 and c=2

(c-4)/(c-2)=(c-2)/(c+2) - 1/(2-c)

- 1/(2-c)=-1/-(c-2)=1/(c-2)

(c-4)/(c-2)=(c-2)/(c+2)+ 1/(c-2)------- > (c-4)/(c-2)-1/(c-2)=(c-2)/(c+2)

(c-4-1)/(c-2)=(c-2)/(c+2)---------------- > (c-5)/(c-2)=(c-2)/(c+2)

(c-5)/(c-2)=(c-2)/(c+2)------------- > remember (before simplifying) for the solution that c can not be 2 or -2

(c-5)*(c+2)=(c-2)*(c-2)------------------ > c²+2c-5c-10=c²-4c+4

-3c-10=-4c+4----------------------------- > -3c+4c=4+10----------- > c=14

the solution is c=14

the domain of the function is (-∞,-2) U (-2,2) U (2,∞) or

all real numbers except c=-2 and c=2