Find the slope of the tangent line to the graph of y= X^2 + 2 at X=1

Differentiate the given function with respect to x. $$ \frac{\differentialD y}{\differentialD x}=\frac{\differentialD}{\differentialD x}\left(x^2+2\right)=2x $$ Now, find the slope of the line tangent to the graph of the function at x = 1. $$ m=\frac{\differentialD y}{\differentialD x}\left(x=1\right)=2\left(1\right), $$ $$ m=2 $$