Determine the equation of a circle with a center at (–4, 0) that passes through the point (–2, 1) by following the steps below. Use the distance formula to determine the radius: Substitute the known values into the standard form: (x – h)² + (y – k)² = r². What is the equation of a circle with a center at (–4, 0) that passes through the point (–2, 1)?

the equation of a line that has a center at (h,k) and radius of r is[tex](x-h)^2+(y-k)^2=r^2[/tex]we can use the distance formula to find the radius ( I would just substitute but whatever)distance between (-4,0) and (-2,1) is[tex]D=\sqrt{(-4-(-2))^2+(0-1)^2}[/tex][tex]D=\sqrt{(-4+2)^2+(-1)^2}[/tex][tex]D=\sqrt{(-2)^2+1}[/tex][tex]D=\sqrt{4+1}[/tex][tex]D=\sqrt{5}[/tex]D=rso the equation is[tex](x-(-4))^2+(y-0)^2=(\sqrt{5})^2[/tex]or[tex](x+4)^2+y^2=5[/tex]