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Choose the equation below whose axis of symmetry is x = 0. (1 point) y = x2 + 2x y = x2 β 16x...
4 months ago
Q:
Choose the equation below whose axis of symmetry is x = 0. (1 point) y = x2 + 2x y = x2 β 16x + 58 y = x2 + 2 y = x2 β 4x + 2
Accepted Solution
A:
The equation y = x^2 has axis of symmetry of Β x = 0
The answer to the question is y = x^2 + 2 Β which is y = x^2 moved vertically up to 2 units