MATH SOLVE

9 months ago

Q:
# ACE, GENIUS, TRUSTED HELPERS!!!!!If x = 2a β b^2 , which expression represents a? SHOW YOUR WORK!!! I already know the answer, I just need help with the work. i am crying right now because no one is answering my questions correctly. people are putting wrong answers or are putting right answers without work. It really isn't nice. A. X + B^2B. (B^2 - x)/2C. (X + B^2)/2D. (x - b^2)/2Please show work!!!I beg of you!

Accepted Solution

A:

Selection C is appropriate.

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Whenever you solve for something, consider what operations are done to that something. Undo them in reverse order.

Here, "a" is

β’ multiplied by 2

β’ has -b^2 added

The last operation is adding -b^2, so we undo that first. We undo it by adding its opposite, b^2.

.. x +b^2 = 2a -b^2 +b^2

.. x +b^2 = 2a . . . . . . . . . . . the point is to cancel the -b^2 term on the right.

The operation before that is multiplying "a" by "2". We undo that by multiplying by the reciprocal of 2, which is 1/2.

.. (1/2)*(x +b^2) = (1/2)*2a

.. (x +b^2)/2 = a . . . . . . . . . the point is to cancel the multiplication by 2 on the right.

You will note this matches answer selection C.

_____

Whenever you solve for something, consider what operations are done to that something. Undo them in reverse order.

Here, "a" is

β’ multiplied by 2

β’ has -b^2 added

The last operation is adding -b^2, so we undo that first. We undo it by adding its opposite, b^2.

.. x +b^2 = 2a -b^2 +b^2

.. x +b^2 = 2a . . . . . . . . . . . the point is to cancel the -b^2 term on the right.

The operation before that is multiplying "a" by "2". We undo that by multiplying by the reciprocal of 2, which is 1/2.

.. (1/2)*(x +b^2) = (1/2)*2a

.. (x +b^2)/2 = a . . . . . . . . . the point is to cancel the multiplication by 2 on the right.

You will note this matches answer selection C.