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A ball is thrown vertically upward from the top of a 200 foot tower, with an initial velocity of 5 f...
8 months ago
Q:
A ball is thrown vertically upward from the top of a 200 foot tower, with an initial velocity of 5 ft/sec. Its position function is s(t) = –16t2 + 5t + 200. What is its velocity in ft/sec when t = 3 seconds?
Accepted Solution
A:
v = ds/dt = -32t + 5
at t = 3 velocity = -96 + 5 = -91 ft/sec answer