MATH SOLVE

8 months ago

Q:
# A ball is thrown vertically upward from the top of a 200 foot tower, with an initial velocity of 5 ft/sec. Its position function is s(t) = –16t2 + 5t + 200. What is its velocity in ft/sec when t = 3 seconds?

Accepted Solution

A:

v = ds/dt = -32t + 5

at t = 3 velocity = -96 + 5 = -91 ft/sec answer

at t = 3 velocity = -96 + 5 = -91 ft/sec answer