A carton has a length of fraction 2 and 2 over 3 feet, width of fraction 1 and 1 over 8 feet, and height of fraction 1 and 1 over 5 feet. What is the volume of the carton?
Accepted Solution
A:
Answer:V = 3.6 ft³Step-by-step explanation:The formula of a volume of rectangular prism:[tex]V=lwh[/tex]l - lengthw - widthh - heightWe have[tex]l=2\dfrac{2}{3}\ ft=\dfrac{(2)(3)+2}{3}\ ft=\dfrac{8}{3}\ dt\\\\w=1\dfrac{1}{8}\ ft=\dfrac{(1)(8)+1}{8}\ ft=\dfrac{9}{8}\ ft\\\\h=1\dfrac{1}{5}\ ft=\dfrac{(1)(5)+1}{5}\ ft=\dfrac{6}{5}\ ft[/tex]Substitute:[tex]V=\left(\dfrac{8}{3}\right)\left(\dfrac{9}{8}\right)\left(\dfrac{6}{5}\right)=\dfrac{432}{120}=3.6\ ft^3[/tex]