5 months ago

((4-3i)×(2+3i))/((5-3i)+(6+2i) )=

Accepted Solution

$\frac{ 8+12i-6i-9{i}^{2} }{ \left( 5-3i \right)+\left( 6+2i \right) }$

$\frac{ 8+12i-6i-9{i}^{2} }{ 5-3i+\left( 6+2i \right) }$

$\frac{ 8+12i-6i-9{i}^{2} }{ 5-3i+6+2i }$

$\frac{ 8+12i-6i-9 \times \left( -1 \right) }{ 5-3i+6+2i }$

$\frac{ 8+12i-6i-9 \times \left( -1 \right) }{ 11-3i+2i }$

$\frac{ 8+12i-6i-9 \times \left( -1 \right) }{ 11-i }$

$\frac{ 8+12i-6i+9 }{ 11-i }$

$\frac{ 17+12i-6i }{ 11-i }$

$\frac{ 17+6i }{ 11-i }$

$\frac{ 181 }{ 122 }+\frac{ 83 }{ 122 }i$

$\frac{ 181 }{ 122 }-\frac{ 83 }{ 122 }i$