MATH SOLVE

6 months ago

Q:
# Which set of segment lenghts could be used to construct a triangle

Accepted Solution

A:

the complete question in the attached figure

we know that

To construct a triangle, two segments added together have to be greater than the 3rd segment,

so

case A)

2, 12, 19

2+12 < 19------> these segments can not be used to form a triangle

case B)

4, 7, 13

4+7 < 13------> these segments can not be used to form a triangle

case C)

4, 5, 12

4+5 < 12------> these segments can not be used to form a triangle

case D)

13, 2, 12

13+2 > 12

13+12> 2

2+12>13

so

these segments can be used to form a triangle

the answer is

the option D)

13, 2, 12

these segments can be used to form a triangle

we know that

To construct a triangle, two segments added together have to be greater than the 3rd segment,

so

case A)

2, 12, 19

2+12 < 19------> these segments can not be used to form a triangle

case B)

4, 7, 13

4+7 < 13------> these segments can not be used to form a triangle

case C)

4, 5, 12

4+5 < 12------> these segments can not be used to form a triangle

case D)

13, 2, 12

13+2 > 12

13+12> 2

2+12>13

so

these segments can be used to form a triangle

the answer is

the option D)

13, 2, 12

these segments can be used to form a triangle