MATH SOLVE

9 months ago

Q:
# what term has to be added to x^2-3x to be a trinomial 3/2 9/4 6 9

Accepted Solution

A:

Your question is probably what should be added to the given expression to make it a perfect square.

The given expression is:

[tex] x^{2} -3x[/tex]

The formula of [tex] (a-b)^{2} [/tex] is [tex] a^{2} -2ab+ b^{2} [/tex]

Re-writing the given expression:

[tex] x^{2} - 2(x)( \frac{3}{2}) [/tex]

So, we have the square of first term and twice the product of first and second term. What is missing is the square of second term.

So, the complete expression for perfect square will be:

[tex] x^{2} -2(x)( \frac{3}{2})+ ( \frac{3}{2} )^{2} \\ \\ x^{2} -2(x)( \frac{3}{2})+ \frac{9}{4} [/tex]

Therefore, 9/4 should be added to the given expression to make it a perfect square.

The given expression is:

[tex] x^{2} -3x[/tex]

The formula of [tex] (a-b)^{2} [/tex] is [tex] a^{2} -2ab+ b^{2} [/tex]

Re-writing the given expression:

[tex] x^{2} - 2(x)( \frac{3}{2}) [/tex]

So, we have the square of first term and twice the product of first and second term. What is missing is the square of second term.

So, the complete expression for perfect square will be:

[tex] x^{2} -2(x)( \frac{3}{2})+ ( \frac{3}{2} )^{2} \\ \\ x^{2} -2(x)( \frac{3}{2})+ \frac{9}{4} [/tex]

Therefore, 9/4 should be added to the given expression to make it a perfect square.