MATH SOLVE

9 months ago

Q:
# Three friends were born in consecutive years. The some of their birth years is 5982.find the year in which each person was born

Accepted Solution

A:

Because the three numbers are consecutive, if the first one is x, the second should be x+1, and the third one is x+2

the three numbers add up to be 5982, so

x+(x+1)+(x+2)=5982

3x+3=5982

3x=5979

x=1993

1993,1994,1995

the three numbers add up to be 5982, so

x+(x+1)+(x+2)=5982

3x+3=5982

3x=5979

x=1993

1993,1994,1995