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Log Nmax = 0.45 Γ Log68
11 months ago
Q:
Log Nmax = 0.45 Γ Log68
Accepted Solution
A:
$$ \log\left(N_{\max}\right)=\log\left(\left(68\right)^{0.45}\right) $$ $$ N_{\max}=\left(0.68\right)^{0.45}\approx6.678 $$