MATH SOLVE

9 months ago

Q:
# Juan put three square tiles with sides 8 centimeters, 10 centimeters, and x centimeters together so that they form a right triangle. Which statement is true about the area A of the smallest tile?

Accepted Solution

A:

since the area of a square is equal to the square of one of its side's length, then the area should be equivalent to [tex] x^{2}[/tex].

[tex] A = x^{2}[/tex] ---> equation (1)

By using pythagoras rule which states that the [tex] x^{2} = hyp^2 - opposite^2[/tex]---> equation (2)

where the opposite side's length is 8 and the hypotenuse side's length is 10

by substituting by the values in equation (2) therefore,

[tex] x^{2} = 10^{2} - 8^{2} [/tex] substitute this value in equation (1) then

[tex] A = x^{2} = 10^{2} -8^{2} [/tex]

where A is the area of the square whose side is x

[tex] A = x^{2}[/tex] ---> equation (1)

By using pythagoras rule which states that the [tex] x^{2} = hyp^2 - opposite^2[/tex]---> equation (2)

where the opposite side's length is 8 and the hypotenuse side's length is 10

by substituting by the values in equation (2) therefore,

[tex] x^{2} = 10^{2} - 8^{2} [/tex] substitute this value in equation (1) then

[tex] A = x^{2} = 10^{2} -8^{2} [/tex]

where A is the area of the square whose side is x