MATH SOLVE

9 months ago

Q:
# It’s my birthday ! I really need help :( it will be my birthday wish:) 1 - 12 please !

Accepted Solution

A:

we know that

To divide two fractions, they multiply "in cross". This is: the numerator of the first fraction by the denominator of the second fraction, thus we get the numerator. To obtain the denominator, we have to multiply the denominator of the first fraction by the numerator of the second fraction

Division of an integer by a fraction or vice versa The unit is put as denominator to the whole and divided as a fraction

we have that

1) 6/(1/2)=6*2/1=12/1=12

2)4/(1/4)=4*4/1=16/1=16

3)5/(1/3)=5*3/1=15/1=15

4)(1/2)/6=1/(6*2)=1/12

5)(1/5)/2=1/(5*2)=1/10

6)(1/8)/3=1/(8*3)=1/24

7)(1/7)/8=1/(7*8)=1/56

8)5/(1/5)=5*5/1=25/1=25

9)(1/3)/9=1/(3*9)=1/27

10)(1/4)/8=1/(4*8)=1/32

11)6/(1/7)=6*7/1=42/1=42

12)(1/6)/5=1/(6*5)=1/30

To divide two fractions, they multiply "in cross". This is: the numerator of the first fraction by the denominator of the second fraction, thus we get the numerator. To obtain the denominator, we have to multiply the denominator of the first fraction by the numerator of the second fraction

Division of an integer by a fraction or vice versa The unit is put as denominator to the whole and divided as a fraction

we have that

1) 6/(1/2)=6*2/1=12/1=12

2)4/(1/4)=4*4/1=16/1=16

3)5/(1/3)=5*3/1=15/1=15

4)(1/2)/6=1/(6*2)=1/12

5)(1/5)/2=1/(5*2)=1/10

6)(1/8)/3=1/(8*3)=1/24

7)(1/7)/8=1/(7*8)=1/56

8)5/(1/5)=5*5/1=25/1=25

9)(1/3)/9=1/(3*9)=1/27

10)(1/4)/8=1/(4*8)=1/32

11)6/(1/7)=6*7/1=42/1=42

12)(1/6)/5=1/(6*5)=1/30