Binomial distribution: find the probability that in 10 tosses of a coin you will get 3 to 6 heads

When tossing a coin, you have 50% chance of landing a head. Now, use the binomial formula to find the probability of landing 3 to 6 heads when a coin is tossed 10 times. $$ P\left(X=x\right)=\left(_nC_x\right)\times p^x\times\left(1-p\right)^{n-x} $$ Where: n = number of trials x = number of successes at n trials p = probability of success As given, n = 10, x = 3 to 6, p = 50% = 0.50 Therefore, $$ P\left(3\le x\le6\right)=\sum_{x\mathop{=}3}^6\left(_{10}C_x\right)\times\left(0.50\right)^x\times\left(1-0.50\right)^{10-x}, $$ $$ P\left(3\le X\le6\right)=0.7734 $$