MATH SOLVE

6 months ago

Q:
# A game has a deck of cards with 10 red cards, 4 blue cards, and 2 yellow cards. You randomly choose two cards. Find the probability of choosing two red cards and a blue card + yellow card

Accepted Solution

A:

The probability of choosing two red cards would be 3/8, and the probability of choosing a blue card and a yellow card would be 1/30.

There are 10+4+2 = 16 cards total.

The probability of choosing 1 red card is 10/16; the probability of choosing a second red card would then be 9/15.

P(2 red) = 10/16(9/15) = 90/240 = 3/8.

The probability of choosing one blue card is 4/16; the probability of choosing a yellow card would then be 2/15.

P(blue and yellow) = 4/16(2/15) = 8/240 = 1/30.

There are 10+4+2 = 16 cards total.

The probability of choosing 1 red card is 10/16; the probability of choosing a second red card would then be 9/15.

P(2 red) = 10/16(9/15) = 90/240 = 3/8.

The probability of choosing one blue card is 4/16; the probability of choosing a yellow card would then be 2/15.

P(blue and yellow) = 4/16(2/15) = 8/240 = 1/30.