Q:

7+8x>-9

Accepted Solution

A:
7+8x>βˆ’9 = 8x>βˆ’9βˆ’7 This simplifies to: 8x>βˆ’16 Now, divide both sides by the coefficient of x, which is 8: $$ \frac{8x}{8}>-\frac{16}{8} $$ x>βˆ’2 So, the solution to the inequality 7+8x>βˆ’9 is x>βˆ’2. This means that any value of x greater than -2 makes the inequality true.