WILL MARK BRAINLIEST!!Write log3 6 as a logarithm of base 2. log base 2 of 3 over log base 2 of 6 log base 2 of 6 over log base 2 of 3 log base 3 of 2 over log base 6 of 2 log base 6 of 2 over log base 3 of 2

The answer is the second option. (log2)6/(log2)3.

Using the change-of-base formula: 
log3(x)=logb(x)/logb(a)

 to write log3(6) as a logarithm of base 2: a = 3, x = 6, b = 2:

log3(6)=log2(6)/log2(3)


hope this helps ^-^