what is the square root of 41 approximated to the nearest tenth

if you calculate √41 to its nearest approximate value,, you would get about 6.40312. now to round this to the nearest tenth,, we must look at the first number behind the decimal. if the number is smaller than 5, you round down but if it is 5 or larger, you round that number up. when you look at our answer of 6.40312, you see that the first number behind the decimal is 4 so we must round down. this means that the correct answer to your question is that 
√41 ≈ 6.4.
let me know if you have any further questions
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