MATH SOLVE

5 months ago

Q:
# What is the solution set to the equation (2x−4)(4x−5)=0

Accepted Solution

A:

First, distribute the parenthesis:

(2x - 4) (4x - 5) = 8x - 20

\___\_/___/

| |

2x * 4x, 4 * 5

Then you add 20 to both sides

8x - 20 = 0

+20 +20

8x = 20

Then you divide both sides by 8

[tex] \frac{8x = 20}{8} [/tex]

x = 2.5

I think I did that right... I don't quite remember what a solution set is

(2x - 4) (4x - 5) = 8x - 20

\___\_/___/

| |

2x * 4x, 4 * 5

Then you add 20 to both sides

8x - 20 = 0

+20 +20

8x = 20

Then you divide both sides by 8

[tex] \frac{8x = 20}{8} [/tex]

x = 2.5

I think I did that right... I don't quite remember what a solution set is