what is the expression in radical form? (7x^3y^2) 2/7
Accepted Solution
A:
[tex] \sqrt[7]{(7x^3y^2)^{2} } = \sqrt[7]{(49x^6y^4)} [/tex] In a fractional exponent the denominator tells what root it is (7th root in this case) and the numerator tells what the value in the parenthesis is raised to (2nd power in this case)