Two worded maths questions. Even if you know one answer it would help! Please also give working out if possible.

Answer: 675 litres 80 mLStep-by-step explanation:1. The total amount of oil in the two tanks at the start is ...   total oil = n + (n +150) + 0 = 2n+150 . . . . litresThe amount of oil in tank C at the end is 1/3 this amount, or   oil in tank C = (total oil)/3 = (2n+150)/3 . . . . litresThe amount pumped into tank C was 500 litres, so we have ...   (2n +150)/3 = 500   2n +150 = 1500 . . . . . . multiply by 3   2n = 1350 . . . . . . . . . . . subtract 150   1350/2 = n = 675 . . . . . divide by the coefficient of n___2. Let x represent the amount remaining in container A. Then 4x is the amount in tank B. Before the transfer, the amount in each container was the same, so ...   x +120 = 4x -120 . . . . . A had 120 more than remains; B had 120 less   240 = 3x . . . . . . . . add 120-x   240/3 = x = 80 . . . divide by the coefficient of xThe amount of liquid left in container A is 80 mL.