MATH SOLVE

3 months ago

Q:
# The solution to the given system of linear equations lies in which quadrant?Ex-3y = 61 x+y=2Quadrant IIIQuadrant !- 54-3 -212345XQuadrant III| Quadrant IV? 17

Accepted Solution

A:

Answer:The solution to the given systems of linear equation is {3, -1} lies in IV Quadrant.Step-by-step explanation:Given:x-3y = 6 ........( 1 ) x+y=2 ........( 2 )To find : x = ?y = ?Solution:Let solve the above equation to get the solutions.Eliminate X by subtracting the two equations equation 1 minus equation 2[tex](x-3y) - (x+y) = 6 - 2\\-4y = 4\\\therefore y=-1[/tex]Now substitute for y = -1 in equation 2 we get[tex]x+(-1)=2\\\therefore x = 2+1\\\therefore x = 3[/tex]Therefore, solution set is {3, -1}InI Quadrant {x,y} = {+,+}......both the coordinates are positive.II Quadrant {x,y} = {-,+}.....X coordinate is negative and Y coordinate is positive.III Quadrant {x,y} = {-,-}......both the coordinates are negative.IV Quadrant {x,y} = {+,-}.....X coordinate is positive and Y coordinate is negative. {3,-1}Point A on the graph is the solution.