The general form of the equation of a circle is 7x2 + 7y2 − 28x + 42y − 35 = 0. The equation of this circle in standard form is ____. The center of the circle is at the point____ , and its radius is_____ units.
Accepted Solution
A:
Answer:The standard form of a circle is (x-h)^2 + (y-k)^2 = r^2 with (h,k) being the center of the circle and r being the radius. In this case the circle's equation in standard form is (x-2)^2 + (y+3)^2 = 18. Knowing this it's easy to see that the center of the circle (h,k) is (2,-3). Finally the radius is [tex]\sqrt{18}[/tex] or in simplified terms, 3[tex]\sqrt{2}[/tex]Step-by-step explanation: